GATEverse Practice, past papers & mock tests

Formula Vault · GA

General Aptitude

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Sheet 1

Percentages, Profit/Loss & Ratios

5 formulas
Percentage Change ☆
\[ \%\Delta = \frac{\text{New}-\text{Old}}{\text{Old}} \times 100 \]
Successive Percentage Change ☆
\[ \text{net} = a+b+\frac{ab}{100} \]
a% then b%
Profit % & Discount ☆
\[ \text{Profit}\% = \frac{SP-CP}{CP}\times 100 \]
Discount% is on Marked Price
Combining Ratios ☆
\[ A{:}B{=}p{:}q,\ B{:}C{=}r{:}s \Rightarrow A{:}B{:}C = pr:qr:qs \]
Compound & Simple Interest ☆
\[ A = P(1+\frac{r}{100})^n \ (\text{CI}) \qquad A = P(1+\frac{rn}{100}) \ (\text{SI}) \]

Can you recall the percentage change formula?

Reveal formula
\[ \%\Delta = \frac{\text{New}-\text{Old}}{\text{Old}} \times 100 \]
Successive % change isn't additive
Successive percentage changes don't simply add -- a% then b% gives a net change of a + b + ab/100, and forgetting the cross term ab/100 is the single most common percentage mistake on GATE-style aptitude questions.
Discount is on Marked Price
Discount is always applied to Marked Price, never Cost Price -- computing it on the wrong base is a frequent, easy-to-miss error in profit/loss problems.
Know which quantity is unknown
'X% of Y' and 'Y is X% of what' are inverse setups -- misreading which quantity is the unknown flips the entire equation; read the problem twice before setting it up.
Scale ratios to a common term
When combining two ratios sharing a common term, the common term must be scaled to a common value (LCM) before combining -- skipping this step gives a wrong combined ratio.
Sheet 2

Time-Speed-Distance & Time-Work

3 formulas
  • Relative speed: same direction |S1-S2|; opposite directions S1+S2
  • Combined work rate = sum of individual rates; time together = 1 / (sum of rates)
Distance-Speed-Time ☆
\[ \text{Distance} = \text{Speed} \times \text{Time} \]
Average Speed (Equal Distances) ☆
\[ \frac{2 S_1 S_2}{S_1+S_2} \]
harmonic mean
Crossing Time ☆
\[ \frac{\text{train length}+L}{\text{speed}} \]

Can you recall the average speed (equal distances) formula?

Reveal formula
\[ \frac{2 S_1 S_2}{S_1+S_2} \]
Equal distances need the harmonic mean
Average speed for EQUAL distances (not equal times) uses the harmonic mean formula 2.S1.S2/(S1+S2), NOT the simple average (S1+S2)/2 -- using arithmetic mean here is the most common time-speed-distance mistake.
Add both lengths when crossing a platform
Train-crossing-a-platform problems must add BOTH the train's own length AND the platform's length to the distance travelled -- forgetting the train's length is a very common setup error.
A leak subtracts from the fill rate
When a leak/outlet pipe works against inlet pipes, its rate is SUBTRACTED -- if the net rate comes out negative, the tank never fills (or empties instead); always sanity-check the sign of the final answer.
Downstream adds, upstream subtracts current
Boat problems: downstream speed = boat speed + current; upstream speed = boat speed - current -- mixing these up flips the whole answer, an easily avoidable slip.
Sheet 3

Permutations, Combinations & Probability

5 formulas
Permutations & Combinations ☆
\[ {}^{n}P_r = \frac{n!}{(n-r)!} \qquad {}^{n}C_r = \frac{n!}{r!(n-r)!} \]
Circular Permutations ☆
\[ (n-1)! \]
n distinct objects
Permutations with Repetition ☆
\[ \frac{n!}{p_1!\,p_2!\cdots p_k!} \]
Union of Events ☆
\[ P(A \cup B) = P(A)+P(B)-P(A \cap B) \]
Independent Events ☆
\[ P(A \cap B) = P(A)\,P(B) \]
only if independent

Can you recall the permutations & combinations formula?

Reveal formula
\[ {}^{n}P_r = \frac{n!}{(n-r)!} \qquad {}^{n}C_r = \frac{n!}{r!(n-r)!} \]
Arrangement vs. selection wording
'Arrangement' problems need permutations (order matters); 'selection/grouping' problems need combinations (order doesn't) -- picking the wrong one based on surface wording, not actual meaning, is the most common setup error in aptitude word problems.
Reflections may need an extra ÷2
Circular permutation (n-1)! applies when only rotations are considered identical -- if reflections are ALSO considered identical, divide by an extra factor of 2. GATE sometimes specifies this explicitly and it's easy to miss.
Repeated letters need dividing out
When objects repeat (e.g. letters of a word), naive n! overcounts -- divide by the factorial of each repeated group's count; forgetting this division is a very common combinatorics mistake.
'At least one' via the complement
'At least one' probability questions are almost always faster via the complement: P(at least one) = 1 - P(none) -- directly summing 'exactly 1 + exactly 2 + ...' is slower and more error-prone.
Sheet 4

Ages, Mixtures & Alligation

2 formulas
  • Mean price in a mixture always lies BETWEEN the two component prices -- sanity-check your alligation ratio against this
  • Ages problems: set up two linear equations from 'present age' and 'age N years ago/hence', then solve simultaneously
Alligation Rule ☆
\[ \frac{\text{Qty cheaper}}{\text{Qty dearer}} = \frac{CP_{dearer} - \text{Mean}}{\text{Mean} - CP_{cheaper}} \]
Repeated Replacement ☆
\[ \text{Final} = \text{Initial} \times \left(1 - \frac{x}{V}\right)^n \]
removing & replacing x out of V, n times

Can you recall the alligation rule formula?

Reveal formula
\[ \frac{\text{Qty cheaper}}{\text{Qty dearer}} = \frac{CP_{dearer} - \text{Mean}}{\text{Mean} - CP_{cheaper}} \]
Alligation ratio order matters
The alligation ratio gives QUANTITIES in the order (dearer's excess) : (cheaper's shortfall) from the mean price -- inverting this ratio is the most common alligation mistake.
Replacement formula applies to concentration
Repeated-replacement problems apply (1 - x/V)^n to the CONCENTRATION, not the absolute quantity removed each round -- the amount of the original substance removed in later rounds is smaller in absolute terms even though the same volume x is drawn out each time.
Age shifts apply to everyone equally
'K years ago' and 'K years hence' both add or subtract K from EVERY person's current age equally -- a common setup error is applying it to only one person's age in the equation.